{
  "id": 75332,
  "title": "Possible new_whale threshold clue",
  "url": "/competitions/humpback-whale-identification/discussion/75332",
  "author_name": "Mario Parreño Lara",
  "post_date": "2018-12-20T16:34:34.649000",
  "votes": 0,
  "comment_count": 0,
  "views": 0,
  "content": "<p>Hi guys!</p>\n\n<p>I saw that only submitting new_whale let us a 0.276 LB score (<a href=\"https://www.kaggle.com/pestipeti/only-new-whale-benchmark\">https://www.kaggle.com/pestipeti/only-new-whale-benchmark</a>)... </p>\n\n<p>Imagine that I do a submission without labels of new whales and I get 0.5 in LB ... is it supposed that looking for a good threshold a good indicator would be that the maximum should be about 0.5 + 0.276?</p>",
  "messages": [
    {
      "id": 442886,
      "postDate": "2018-12-20T16:34:34.650Z",
      "content": "<p>Hi guys!</p>\n\n<p>I saw that only submitting new_whale let us a 0.276 LB score (<a href=\"https://www.kaggle.com/pestipeti/only-new-whale-benchmark\">https://www.kaggle.com/pestipeti/only-new-whale-benchmark</a>)... </p>\n\n<p>Imagine that I do a submission without labels of new whales and I get 0.5 in LB ... is it supposed that looking for a good threshold a good indicator would be that the maximum should be about 0.5 + 0.276?</p>",
      "rawMarkdown": "Hi guys!\n\nI saw that only submitting new_whale let us a 0.276 LB score (https://www.kaggle.com/pestipeti/only-new-whale-benchmark)... \n\nImagine that I do a submission without labels of new whales and I get 0.5 in LB ... is it supposed that looking for a good threshold a good indicator would be that the maximum should be about 0.5 + 0.276?"
    }
  ],
  "comments": [],
  "raw_markdown_by_id": {
    "442886": "Hi guys!\n\nI saw that only submitting new_whale let us a 0.276 LB score (https://www.kaggle.com/pestipeti/only-new-whale-benchmark)... \n\nImagine that I do a submission without labels of new whales and I get 0.5 in LB ... is it supposed that looking for a good threshold a good indicator would be that the maximum should be about 0.5 + 0.276?"
  }
}